Difference between revisions of "Talk:Geometric inequality"

Revision as of 23:09, 28 April 2008

Shouldn't the sign for the Isoperimetric Inequality be $\le$ not $<$ since a circle is a figure and $\frac{4 \pi (\pi r^{2})}{(2 \pi r)^{2}}=1$ ?

--Xantos C. Guin 19:26, 24 June 2006 (EDT)

That's what I think, too.

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-Shouldn't the sign for the Isoperimetric Inequality be <math>\displaystyle \le </math> not <math>\displaystyle < </math> since a circle is a figure and <math>\displaystyle \frac{4 \pi (\pi r^{2})}{(2 \pi r)^{2}}=1 </math>?
+Shouldn't the sign for the Isoperimetric Inequality be <math>\le </math> not <math>< </math> since a circle is a figure and <math>\frac{4 \pi (\pi r^{2})}{(2 \pi r)^{2}}=1 </math>?
 --[[User:Xantos C. Guin|Xantos C. Guin]] 19:26, 24 June 2006 (EDT)
 That's what I think, too.
+--[[Users:CLee|CLee]]