Difference between revisions of "1988 AJHSME Problems"
5849206328x (talk | contribs) (New page: == Problem 1 == The diagram shows part of a scale of a measuring device. The arrow indicates an approximate reading of {{image}} <math>\text{(A)}\ 10.05 \qquad \text{(B)}\ 10.15 \qquad...) |
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The diagram shows part of a scale of a measuring device. The arrow indicates an approximate reading of | The diagram shows part of a scale of a measuring device. The arrow indicates an approximate reading of | ||
− | + | <asy> | |
+ | draw((-3,0)..(0,3)..(3,0)); | ||
+ | draw((-3.5,0)--(-2.5,0)); | ||
+ | draw((0,2.5)--(0,3.5)); | ||
+ | draw((2.5,0)--(3.5,0)); | ||
+ | draw((1.8,1.8)--(2.5,2.5)); | ||
+ | draw((-1.8,1.8)--(-2.5,2.5)); | ||
+ | draw((0,0)--3*dir(120),EndArrow); | ||
+ | label("$10$",(-2.6,0),E); | ||
+ | label("$11$",(2.6,0),W); | ||
+ | </asy> | ||
<math>\text{(A)}\ 10.05 \qquad \text{(B)}\ 10.15 \qquad \text{(C)}\ 10.25 \qquad \text{(D)}\ 10.3 \qquad \text{(E)}\ 10.6</math> | <math>\text{(A)}\ 10.05 \qquad \text{(B)}\ 10.15 \qquad \text{(C)}\ 10.25 \qquad \text{(D)}\ 10.3 \qquad \text{(E)}\ 10.6</math> | ||
Line 10: | Line 20: | ||
== Problem 2 == | == Problem 2 == | ||
+ | |||
+ | The product <math>8\times .25\times 2\times .125 =</math> | ||
+ | |||
+ | <math>\text{(A)}\ \frac18 \qquad \text{(B)}\ \frac14 \qquad \text{(C)}\ \frac12 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 2</math> | ||
[[1988 AJHSME Problems/Problem 2|Solution]] | [[1988 AJHSME Problems/Problem 2|Solution]] | ||
== Problem 3 == | == Problem 3 == | ||
+ | |||
+ | <math>\frac{1}{10}+\frac{2}{20}+\frac{3}{30} = </math> | ||
+ | |||
+ | <math>\text{(A)}\ .1 \qquad \text{(B)}\ .123 \qquad \text{(C)}\ .2 \qquad \text{(D)}\ .3 \qquad \text{(E)}\ .6</math> | ||
[[1988 AJHSME Problems/Problem 3|Solution]] | [[1988 AJHSME Problems/Problem 3|Solution]] | ||
Line 26: | Line 44: | ||
== Problem 6 == | == Problem 6 == | ||
+ | |||
+ | <math>\frac{(.2)^3}{(.02)^2} =</math> | ||
+ | |||
+ | <math>\text{(A)}\ .2 \qquad \text{(B)}\ 2 \qquad \text{(C)}\ 10 \qquad \text{(D)}\ 15 \qquad \text{(E)}\ 20</math> | ||
[[1988 AJHSME Problems/Problem 6|Solution]] | [[1988 AJHSME Problems/Problem 6|Solution]] | ||
== Problem 7 == | == Problem 7 == | ||
+ | |||
+ | <math>2.46\times 8.163\times (5.17+4.829)</math> is closest to | ||
+ | |||
+ | <math>\text{(A)}\ 100 \qquad \text{(B)}\ 200 \qquad \text{(C)}\ 300 \qquad \text{(D)}\ 400 \qquad \text{(E)}\ 500</math> | ||
[[1988 AJHSME Problems/Problem 7|Solution]] | [[1988 AJHSME Problems/Problem 7|Solution]] | ||
== Problem 8 == | == Problem 8 == | ||
+ | |||
+ | Betty used a calculator to find the product <math>0.075 \times 2.56</math>. She forgot to enter the decimal points. The calculator showed <math>19200</math>. If Betty had entered the decimal points correctly, the answer would have been | ||
+ | |||
+ | <math>\text{(A)}\ .0192 \qquad \text{(B)}\ .192 \qquad \text{(C)}\ 1.92 \qquad \text{(D)}\ 19.2 \qquad \text{(E)}\ 192</math> | ||
[[1988 AJHSME Problems/Problem 8|Solution]] | [[1988 AJHSME Problems/Problem 8|Solution]] | ||
Line 42: | Line 72: | ||
== Problem 10 == | == Problem 10 == | ||
+ | |||
+ | Chris' birthday is on a Thursday this year. What day of the week will it be <math>60</math> days after her birthday? | ||
+ | |||
+ | <math>\text{(A)}\ \text{Monday} \qquad \text{(B)}\ \text{Wednesday} \qquad \text{(C)}\ \text{Thursday} \qquad \text{(D)}\ \text{Friday} \qquad \text{(E)}\ \text{Saturday}</math> | ||
[[1988 AJHSME Problems/Problem 10|Solution]] | [[1988 AJHSME Problems/Problem 10|Solution]] | ||
== Problem 11 == | == Problem 11 == | ||
+ | |||
+ | <math>\sqrt{164}</math> is | ||
+ | |||
+ | <math>\text{(A)}\ 42 \qquad \text{(B)}\ \text{less than }10 \qquad \text{(C)}\ \text{between }10\text{ and }11 \qquad \text{(D)}\ \text{between }11\text{ and }12 \qquad \text{(E)}\ \text{between }12\text{ and }13</math> | ||
[[1988 AJHSME Problems/Problem 11|Solution]] | [[1988 AJHSME Problems/Problem 11|Solution]] | ||
== Problem 12 == | == Problem 12 == | ||
+ | |||
+ | Suppose the estimated <math>20</math> billion dollar cost to send a person to the planet Mars is shared equally by the <math>250</math> million people in the U.S. Then each person's share is | ||
+ | |||
+ | <math>\text{(A)}\ 40\text{ dollars} \qquad \text{(B)}\ 50\text{ dollars} \qquad \text{(C)}\ 80\text{ dollars} \qquad \text{(D)}\ 100\text{ dollars} \qquad \text{(E)}\ 125\text{ dollars}</math> | ||
[[1988 AJHSME Problems/Problem 12|Solution]] | [[1988 AJHSME Problems/Problem 12|Solution]] |
Revision as of 11:38, 15 March 2009
Contents
- 1 Problem 1
- 2 Problem 2
- 3 Problem 3
- 4 Problem 4
- 5 Problem 5
- 6 Problem 6
- 7 Problem 7
- 8 Problem 8
- 9 Problem 9
- 10 Problem 10
- 11 Problem 11
- 12 Problem 12
- 13 Problem 13
- 14 Problem 14
- 15 Problem 15
- 16 Problem 16
- 17 Problem 17
- 18 Problem 18
- 19 Problem 19
- 20 Problem 20
- 21 Problem 21
- 22 Problem 22
- 23 Problem 23
- 24 Problem 24
- 25 Problem 25
- 26 See also
Problem 1
The diagram shows part of a scale of a measuring device. The arrow indicates an approximate reading of
Problem 2
The product
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
is closest to
Problem 8
Betty used a calculator to find the product . She forgot to enter the decimal points. The calculator showed
. If Betty had entered the decimal points correctly, the answer would have been
Problem 9
Problem 10
Chris' birthday is on a Thursday this year. What day of the week will it be days after her birthday?
Problem 11
is
Problem 12
Suppose the estimated billion dollar cost to send a person to the planet Mars is shared equally by the
million people in the U.S. Then each person's share is