Difference between revisions of "2011 AMC 12B Problems/Problem 1"
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− | + | \boxed{\frac{7}{12}\ \textbf{(C)}} | |
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== See also == | == See also == | ||
{{AMC12 box|year=2011|before=First Problem|num-a=2|ab=B}} | {{AMC12 box|year=2011|before=First Problem|num-a=2|ab=B}} |
Revision as of 16:02, 27 February 2011
Problem
What is
Solution
Add up the numbers in each fraction to get , which equals
. Doing the subtraction yields
See also
2011 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by First Problem |
Followed by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |