Difference between revisions of "1993 AHSME Problems"
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== Problem 2 == | == Problem 2 == | ||
− | In <math>\triangle ABC</math>, <math>\angle A=55\circ</math>, <math>\angle C=75\circ</math>, <math>D</math> is on side <math>\ | + | In <math>\triangle ABC</math>, <math>\angle A=55^\circ</math>, <math>\angle C=75^\circ</math>, <math>D</math> is on side <math>\overline{AB}</math> and <math>E</math> is on side <math>\overline{BC}</math> If <math>DB=BE</math>, then <math>\angle BED=</math> |
− | <math>\text{(A)}\ 50\circ \qquad | + | <math>\text{(A)}\ 50^\circ \qquad |
− | \text{(B)}\ 55\circ \qquad | + | \text{(B)}\ 55^\circ \qquad |
− | \text{(C)}\ 60\circ \qquad | + | \text{(C)}\ 60^\circ \qquad |
− | \text{(D)}\ 65\circ \qquad | + | \text{(D)}\ 65^\circ \qquad |
− | \text{(E)}\ 70\circ </math> | + | \text{(E)}\ 70^\circ </math> |
Revision as of 22:07, 28 February 2011
Contents
[hide]- 1 Problem 1
- 2 Problem 2
- 3 Problem 3
- 4 Problem 4
- 5 Problem 5
- 6 Problem 6
- 7 Problem 7
- 8 Problem 8
- 9 Problem 9
- 10 Problem 10
- 11 Problem 11
- 12 Problem 12
- 13 Problem 13
- 14 Problem 14
- 15 Problem 15
- 16 Problem 16
- 17 Problem 17
- 18 Problem 18
- 19 Problem 19
- 20 Problem 20
- 21 Problem 21
- 22 Problem 22
- 23 Problem 23
- 24 Problem 24
- 25 Problem 25
- 26 Problem 26
- 27 Problem 27
- 28 Problem 28
- 29 Problem 29
- 30 Problem 30
- 31 See also
Problem 1
For integers and , define to mean . Then equals
Problem 2
In , , , is on side and is on side If , then
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22