Difference between revisions of "1998 AJHSME Problems/Problem 1"
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* [[AJHSME Problems and Solutions]] | * [[AJHSME Problems and Solutions]] | ||
* [[Mathematics competition resources]] | * [[Mathematics competition resources]] |
Revision as of 23:06, 9 June 2011
Contents
[hide]Problem 1
For , which of the following is the smallest?
Solution 1
The smallest fraction would be in the form where is larger than .
In this problem, we would need the largest possible value out of all the given values to be in the denominator. This value is or
The smaller would go on the nominator, which is .
The answer choice with is
Solution 2
Plugging in for every answer choice would give
From here, we can see that the smallest is answer choice
See also
1998 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by First question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |