Difference between revisions of "2005 AMC 12B Problems/Problem 19"
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== See also == | == See also == | ||
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Revision as of 13:55, 4 July 2011
Problem
Let and
be two-digit integers such that
is obtained by reversing the digits of
. The integers
and
satisfy
for some positive integer
. What is
?
Solution
let , then
where
and
are nonzero digits.
By difference of squares,
For this product to be a square, the factor of must be repeated in either
or
, and given the constraints it has to be
. The factor of
is already a square and can be ignored. Now
must be another square, and since
cannot be
or greater then
must equal
or
. If
then
,
,
, which is not a digit. Hence the only possible value for
is
. Now we have
,
,
, then
,
,
,
, and
See also
2005 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 18 |
Followed by Problem 20 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |