Difference between revisions of "1995 AHSME Problems/Problem 14"
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== Solution == | == Solution == | ||
− | <math>f(-x) = a(-x)^4 - b(-x)^2 - x + 5 | + | <math>f(-x) = a(-x)^4 - b(-x)^2 - x + 5</math> |
− | < | + | <math>f(-x) = ax^4 - bx^2 - x + 5</math> |
<math>f(-x) = (ax^4 + bx^2 + x + 5) - 2x</math> | <math>f(-x) = (ax^4 + bx^2 + x + 5) - 2x</math> |
Revision as of 16:37, 18 August 2011
Problem
If and , then
Solution
.
Thus .
See also
1995 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |