Difference between revisions of "2010 AMC 8 Problems/Problem 3"
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The highest price was in Month 1, which was $17. The lowest price was in Month 3, which was $10. 17 is <math>\frac{17}{10}\cdot100=170%</math> of 10, and is <math>170-100=70%</math> more than 10. | The highest price was in Month 1, which was $17. The lowest price was in Month 3, which was $10. 17 is <math>\frac{17}{10}\cdot100=170%</math> of 10, and is <math>170-100=70%</math> more than 10. | ||
Therefore, the answer is <math> \boxed{\textbf{(C)}\ 70}</math> | Therefore, the answer is <math> \boxed{\textbf{(C)}\ 70}</math> | ||
+ | ==See Also== | ||
+ | {{AMC8 box|year=2010|num-b=2|num-a=4}} |
Revision as of 13:07, 28 May 2012
Problem
The graph shows the price of five gallons of gasoline during the first ten months of the year. By what percent is the highest price more than the lowest price?
Solution
The highest price was in Month 1, which was $17. The lowest price was in Month 3, which was $10. 17 is $\frac{17}{10}\cdot100=170%$ (Error compiling LaTeX. Unknown error_msg) of 10, and is $170-100=70%$ (Error compiling LaTeX. Unknown error_msg) more than 10. Therefore, the answer is
See Also
2010 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |