Difference between revisions of "2011 AMC 12B Problems/Problem 1"

Revision as of 10:02, 4 July 2013

Problem

What is $\frac{2+4+6}{1+3+5} - \frac{1+3+5}{2+4+6}?$

$\textbf{(A)}\ -1 \qquad \textbf{(B)}\ \frac{5}{36} \qquad \textbf{(C)}\ \frac{7}{12} \qquad \textbf{(D)}\ \frac{147}{60} \qquad \textbf{(E)}\ \frac{43}{3}$

Solution

Add up the numbers in each fraction to get $\frac{12}{9} - \frac{9}{12}$ , which equals $\frac{4}{3} - \frac{3}{4}$ . Doing the subtraction yields $\boxed{\frac{7}{12}\ \textbf{(C)}}$

2011 AMC 12B (Problems • Answer Key • Resources)
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The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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 == See also ==
 {{AMC12 box|year=2011|before=First Problem|num-a=2|ab=B}}
+{{MAA Notice}}

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Difference between revisions of "2011 AMC 12B Problems/Problem 1"

Revision as of 10:02, 4 July 2013

Problem

Solution

See also