Difference between revisions of "2001 AMC 8 Problems/Problem 12"

Revision as of 23:38, 4 July 2013

If $a\otimes b = \dfrac{a + b}{a - b}$ , then $(6\otimes 4)\otimes 3 =$

$\text{(A)}\ 4 \qquad \text{(B)}\ 13 \qquad \text{(C)}\ 15 \qquad \text{(D)}\ 30 \qquad \text{(E)}\ 72$

$6\otimes4=\frac{6+4}{6-4}=5$ . $5\otimes3=\frac{5+3}{5-3}=4, \boxed{\text{A}}$

2001 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 11	Followed by Problem 13
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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 ==See Also==
 {{AMC8 box|year=2001|num-b=11|num-a=13}}
+{{MAA Notice}}