Difference between revisions of "2001 AIME II Problems/Problem 14"
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*Case One : <math>cis{28}\theta</math> = <math>\frac{1}{2}+ \frac{\sqrt{3}}{2}i</math> and <math>cis {8}\theta</math> = <math>-\frac{1}{2}+\frac{\sqrt{3}}{2}i</math> | *Case One : <math>cis{28}\theta</math> = <math>\frac{1}{2}+ \frac{\sqrt{3}}{2}i</math> and <math>cis {8}\theta</math> = <math>-\frac{1}{2}+\frac{\sqrt{3}}{2}i</math> | ||
− | Setting up and solving equations, <math>Z^{28}= cis{60^\circ</math> and <math>Z^8= cis{120^\circ</math>, we see that the | + | Setting up and solving equations, <math>Z^{28}= cis{60^\circ</math> and <math>Z^8= cis{120^\circ</math>, we see that the solutions common to both equations have arguments <math>15^\circ , 105^\circ, 195^\circ, </math> and <math>\ 285^\circ</math> |
*Case 2 : <math>cis{28}\theta</math> = <math>\frac{1}{2} -\frac {\sqrt{3}}{2}i</math> and <math>cis {8}\theta</math> = <math>-\frac {1}{2} -\frac{\sqrt{3}}{2}i</math> | *Case 2 : <math>cis{28}\theta</math> = <math>\frac{1}{2} -\frac {\sqrt{3}}{2}i</math> and <math>cis {8}\theta</math> = <math>-\frac {1}{2} -\frac{\sqrt{3}}{2}i</math> | ||
− | Again setting up equations (<math>Z^{28}= cis{300^\circ</math> and <math>Z^{8} = cis{240^\circ</math>) we see that the | + | Again setting up equations (<math>Z^{28}= cis{300^\circ</math> and <math>Z^{8} = cis{240^\circ</math>) we see that the common solutions have arguments of <math>75^\circ, 165^\circ, 255^\circ, </math> and <math>345^\circ</math> |
Listing all of these values, it is seen that <math>\theta_{2} + \theta_{4} + \ldots + \theta_{2n}</math> is equal to <math>(75 + 165 + 255 + 345) ^\circ</math> which is equal to <math>\boxed {840}</math> degrees | Listing all of these values, it is seen that <math>\theta_{2} + \theta_{4} + \ldots + \theta_{2n}</math> is equal to <math>(75 + 165 + 255 + 345) ^\circ</math> which is equal to <math>\boxed {840}</math> degrees |
Revision as of 09:51, 22 August 2014
Problem
There are complex numbers that satisfy both and . These numbers have the form , where and angles are measured in degrees. Find the value of .
Contents
Solution
Z can be written in the form . Rearranging, we get that =
Since the real part of is one more than the real part of and their imaginary parts are equal, it is clear that either = and = , or = and =
- Case One : = and =
Setting up and solving equations, $Z^{28}= cis{60^\circ$ (Error compiling LaTeX. Unknown error_msg) and $Z^8= cis{120^\circ$ (Error compiling LaTeX. Unknown error_msg), we see that the solutions common to both equations have arguments and
- Case 2 : = and =
Again setting up equations ($Z^{28}= cis{300^\circ$ (Error compiling LaTeX. Unknown error_msg) and $Z^{8} = cis{240^\circ$ (Error compiling LaTeX. Unknown error_msg)) we see that the common solutions have arguments of and
Listing all of these values, it is seen that is equal to which is equal to degrees
See also
2001 AIME II (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.