Difference between revisions of "2014 AMC 8 Problems/Problem 1"
Mathonator (talk | contribs) |
Mathonator (talk | contribs) |
||
| Line 4: | Line 4: | ||
<math>\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad \textbf{(E) }10</math> | <math>\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad \textbf{(E) }10</math> | ||
| − | {{AMC8 box|year=2014|num-b= | + | ==See Also== |
| + | {{AMC8 box|year=2014|num-b=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 18:03, 26 November 2014
Harry and Terry are each told to calculate 8-(2-5). Harry gets the correct answer. Terry ignores the parentheses and calculates 8-2+5. If Harry's answer is H and Terry's answer is T, what is H-T?
See Also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
