Difference between revisions of "2014 AMC 8 Problems/Problem 24"

Line 3: Line 3:
 
Note: <math>1</math> mile= <math>5280</math> feet
 
Note: <math>1</math> mile= <math>5280</math> feet
  
 +
<asy>
 +
size(10cm); pathpen=black; pointpen=black;
 +
D(arc((-2,0),1,300,360));
 +
D(arc((0,0),1,0,180));
 +
D(arc((2,0),1,180,360));
 +
D(arc((4,0),1,0,180));
 +
D(arc((6,0),1,180,240));
 +
D((-1.5,1)--(5.5,1));
 +
D((-1.5,0)--(5.5,0),dashed);
 +
D((-1.5,-1)--(5.5,-1));
 +
</asy>
 +
 +
<math> \textbf{(A) }\frac{\pi}{11}\qquad\textbf{(B) }\frac{\pi}{10}\qquad\textbf{(C) }\frac{\pi}{5}\qquad\textbf{(D) }\frac{2\pi}{5}\qquad\textbf{(E) }\frac{2\pi}{3} </math>
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2014|num-b=23|num-a=25}}
 
{{AMC8 box|year=2014|num-b=23|num-a=25}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 19:31, 26 November 2014

A straight one-mile stretch of highway, $40$ feet wide, is closed. Robert rides his bike on a path composed of semicircles as shown. If he rides at $5$ miles per hour, how many hours will it take to cover the one-mile stretch?

Note: $1$ mile= $5280$ feet

[asy] size(10cm); pathpen=black; pointpen=black; D(arc((-2,0),1,300,360)); D(arc((0,0),1,0,180)); D(arc((2,0),1,180,360)); D(arc((4,0),1,0,180)); D(arc((6,0),1,180,240)); D((-1.5,1)--(5.5,1)); D((-1.5,0)--(5.5,0),dashed); D((-1.5,-1)--(5.5,-1)); [/asy]

$\textbf{(A) }\frac{\pi}{11}\qquad\textbf{(B) }\frac{\pi}{10}\qquad\textbf{(C) }\frac{\pi}{5}\qquad\textbf{(D) }\frac{2\pi}{5}\qquad\textbf{(E) }\frac{2\pi}{3}$

See Also

2014 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 23
Followed by
Problem 25
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png