Difference between revisions of "2014 AMC 8 Problems/Problem 24"
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| + | One day the Beverage Barn sold <math>252</math> cans of soda to <math>100</math> customers, and every customer bough at least one can of soda. What is the maximum possible median number of cans of soda bought per customer on that day? | ||
| + | <math>\textbf{(A) }2.5\qquad\textbf{(B) }3.0\qquad\textbf{(C) }3.5\qquad\textbf{(D) }4.0\qquad \textbf{(E) }4.5</math> | ||
| + | |||
| + | ==See also== | ||
{{AMC8 box|year=2014|num-b=23|num-a=25}} | {{AMC8 box|year=2014|num-b=23|num-a=25}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 19:32, 26 November 2014
One day the Beverage Barn sold 
cans of soda to 
customers, and every customer bough at least one can of soda. What is the maximum possible median number of cans of soda bought per customer on that day?
See also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
