Difference between revisions of "2014 AMC 8 Problems/Problem 16"
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The "Middle School Eight" basketball conference has <math>8</math> teams. Every season, each team plays every other conference team twice (home and away), and each team also plays <math>4</math> games against non-conference opponents. What is the total number of games in a season involving the "Middle School Eight" teams? | The "Middle School Eight" basketball conference has <math>8</math> teams. Every season, each team plays every other conference team twice (home and away), and each team also plays <math>4</math> games against non-conference opponents. What is the total number of games in a season involving the "Middle School Eight" teams? | ||
Revision as of 19:40, 26 November 2014
Problem
The "Middle School Eight" basketball conference has 
teams. Every season, each team plays every other conference team twice (home and away), and each team also plays 
games against non-conference opponents. What is the total number of games in a season involving the "Middle School Eight" teams?
See Also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 15 |
Followed by Problem 17 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
