Difference between revisions of "2014 AMC 8 Problems/Problem 4"
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==Solution== | ==Solution== | ||
| − | Since the two prime numbers sum to an odd number, one of them must be even. The only even prime number is <math>2</math>. The other prime number is <math>85-2=83</math>, and the product of these two numbers is <math>83\cdot2=\boxed{166}</math>. | + | Since the two prime numbers sum to an odd number, one of them must be even. The only even prime number is <math>2</math>. The other prime number is <math>85-2=83</math>, and the product of these two numbers is <math>83\cdot2=\boxed{166}</math>. So the answer is <math>\boxed{E}</math> |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2014|num-b=3|num-a=5}} | {{AMC8 box|year=2014|num-b=3|num-a=5}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 15:38, 3 November 2015
Problem
The sum of two prime numbers is 
. What is the product of these two prime numbers?
Solution
Since the two prime numbers sum to an odd number, one of them must be even. The only even prime number is 
. The other prime number is 
, and the product of these two numbers is 
. So the answer is 
See Also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
