Difference between revisions of "2014 AIME II Problems/Problem 15"
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Let the prime factorization of <math>x_i</math> be written as <math>p_{a_1} \cdot p_{a_2} \cdot p_{a_3} \cdots</math>, where <math>p_i</math> is the <math>i</math>th prime number. Then, for every <math>p_{a_k}</math> in the prime factorization of <math>x_i</math>, place a <math>1</math> in the <math>a_k</math>th digit of <math>y_i</math>. This will result in the conversion <math>x_1 = 2, x_{2} = 3, x_{3} = 2 * 3 = 6, \cdots</math>. | Let the prime factorization of <math>x_i</math> be written as <math>p_{a_1} \cdot p_{a_2} \cdot p_{a_3} \cdots</math>, where <math>p_i</math> is the <math>i</math>th prime number. Then, for every <math>p_{a_k}</math> in the prime factorization of <math>x_i</math>, place a <math>1</math> in the <math>a_k</math>th digit of <math>y_i</math>. This will result in the conversion <math>x_1 = 2, x_{2} = 3, x_{3} = 2 * 3 = 6, \cdots</math>. | ||
− | Multiplication for the sequence <math>x_i</math> will translate to addition for the sequence <math>y_i</math>. Thus, we see that <math>x_{n+1}X(x_n) = x_np(x_n)</math> translates into <math>y_{n+1} = y_n+1</math>. Since <math>x_0=1, and y_0=0</math>, <math>x_i</math> corresponds to <math>y_i</math>, which is <math>i</math> in binary. Since <math>x_{ | + | Multiplication for the sequence <math>x_i</math> will translate to addition for the sequence <math>y_i</math>. Thus, we see that <math>x_{n+1}X(x_n) = x_np(x_n)</math> translates into <math>y_{n+1} = y_n+1</math>. Since <math>x_0=1, and y_0=0</math>, <math>x_i</math> corresponds to <math>y_i</math>, which is <math>i</math> in binary. Since <math>x_{10010101_2} = 2 \cdot 5 \cdot 11 \cdot 19 = 2090</math>, <math>t = 10010101_2</math> = <math>\boxed{149}</math>. |
== See also == | == See also == | ||
{{AIME box|year=2014|n=II|num-b=14|after=Last Problem}} | {{AIME box|year=2014|n=II|num-b=14|after=Last Problem}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 22:05, 10 January 2016
Problem
For any integer , let
be the smallest prime which does not divide
Define the integer function
to be the product of all primes less than
if
, and
if
Let
be the sequence defined by
, and
for
Find the smallest positive integer
such that
Solution
Note that for any , for any prime
,
. This provides motivation to translate
into a binary sequence
.
Let the prime factorization of be written as
, where
is the
th prime number. Then, for every
in the prime factorization of
, place a
in the
th digit of
. This will result in the conversion
.
Multiplication for the sequence will translate to addition for the sequence
. Thus, we see that
translates into
. Since
,
corresponds to
, which is
in binary. Since
,
=
.
See also
2014 AIME II (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Last Problem | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.