Difference between revisions of "1968 AHSME Problems/Problem 4"

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== Solution ==
 
== Solution ==
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<math>4 \star 4 \star 4 = 4 \star 2 = \frac{4}{3}</math>
 
<math>\fbox{C}</math>
 
<math>\fbox{C}</math>
  

Revision as of 12:42, 28 July 2016

Problem

Define an operation $\star$ for positive real numbers as $a\star b=\frac{ab}{a+b}$. Then $4 \star (4 \star 4)$ equals:

$\text{(A) } \frac{3}{4}\quad \text{(B) } 1\quad \text{(C) } \frac{4}{3}\quad \text{(D) } 2\quad \text{(E )} \frac{16}{3}$


Solution

$4 \star 4 \star 4 = 4 \star 2 = \frac{4}{3}$ $\fbox{C}$

See also

1968 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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