Difference between revisions of "1998 AJHSME Problems/Problem 2"

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== Problem ==
 
== Problem ==
  
If <math>\begin{tabular}{r|l}a&b \ \hline c&d\end{tabular} = \text{a}\cdot \text{d} - \text{b}\cdot \text{c}</math>, what is the value of <math>Unknown environment 'tabular'</math>?
+
If <math>\begin{tabular}{r|l}a&c \ \hline c&d\end{tabular} = \text{a}\cdot \text{d} - \text{b}\cdot \text{c}</math>, what is the value of <math>Unknown environment 'tabular'</math>?
  
 
<math>\text{(A)}\ -2 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 0 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 2</math>
 
<math>\text{(A)}\ -2 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 0 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 2</math>

Revision as of 14:39, 20 October 2016

Problem

If $\begin{tabular}{r|l}a&c \\ \hline c&d\end{tabular} = \text{a}\cdot \text{d} - \text{b}\cdot \text{c}$, what is the value of $\begin{tabular}{r|l}3&4 \\ \hline 1&2\end{tabular}$?

$\text{(A)}\ -2 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 0 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 2$

Solution

Plugging in values for $a$, $b$, $c$, and $d$, we get

$a=3$, $b=4$, $c=1$, $d=2$,

$a\times d=3\times2=6$

$b\times c=4\times1=4$

$6-4=2$

$\boxed{E}$

See also

1998 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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