Difference between revisions of "2017 AMC 10A Problems/Problem 4"
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==Solution== | ==Solution== | ||
Every <math>30</math> seconds <math>3-2</math> toys are put in the box, so after <math>27\cdot30seconds</math> there will be <math>27</math> toys in the box. Mia's mom will then put <math>3</math> toys into to the box and we have our total amount of time to be <math>27\cdot30+30=840</math> seconds, which equals <math>14</math> minutes. <math>\boxed{(B) 14}</math> | Every <math>30</math> seconds <math>3-2</math> toys are put in the box, so after <math>27\cdot30seconds</math> there will be <math>27</math> toys in the box. Mia's mom will then put <math>3</math> toys into to the box and we have our total amount of time to be <math>27\cdot30+30=840</math> seconds, which equals <math>14</math> minutes. <math>\boxed{(B) 14}</math> | ||
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+ | ==See Also== | ||
+ | {{AMC10 box|year=2017|ab=A|num-b=3|num-a=5}} | ||
+ | {{MAA Notice}} |
Revision as of 15:38, 8 February 2017
Problem
Mia is “helping” her mom pick up toys that are strewn on the floor. Mia’s mom manages to put toys into the toy box every seconds, but each time immediately after those seconds have elapsed, Mia takes toys out of the box. How much time, in minutes, will it take Mia and her mom to put all toys into the box for the first time?
Solution
Every seconds toys are put in the box, so after there will be toys in the box. Mia's mom will then put toys into to the box and we have our total amount of time to be seconds, which equals minutes.
See Also
2017 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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