Difference between revisions of "2007 UNCO Math Contest II Problems/Problem 7"
Mathisfun04 (talk | contribs) (→Solution) |
Mitko pitko (talk | contribs) m (→Solution) |
||
Line 9: | Line 9: | ||
== Solution == | == Solution == | ||
− | Part A: Knowing that the formula for an infinite geometric series is <math>A/(1 - r)</math>, where <math>A</math> and <math>r</math> are the first term and common ratio respectively, we compute <math>1/(1 - 1/3) = 3/2</math>, and we have our answer of <math>2 | + | Part A: Knowing that the formula for an infinite geometric series is <math>A/(1 - r)</math>, where <math>A</math> and <math>r</math> are the first term and common ratio respectively, we compute <math>1/(1 - 1/3) = 3/2</math>, and we have our answer of <math>3/2</math>. |
Revision as of 07:50, 30 January 2018
Problem
(a) Express the infinite sum as a reduced fraction.
(b) Express the infinite sum as a reduced fraction. Here the denominators are powers of and the numerators are the Fibonacci numbers where .
Solution
Part A: Knowing that the formula for an infinite geometric series is , where and are the first term and common ratio respectively, we compute , and we have our answer of .
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See Also
2007 UNCO Math Contest II (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
All UNCO Math Contest Problems and Solutions |