2020 AMC 8 Problems/Problem 2

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Problem 2

Four friends do yardwork for their neighbors over the weekend, earning $$15, $20, $25,$ and $$40,$ respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned $$40$ give to the others?

$\textbf{(A) }$5 \qquad \textbf{(B) }$10 \qquad \textbf{(C) }$15 \qquad \textbf{(D) }$20 \qquad \textbf{(E) }$25$

Solution

First we average $15,20,25,40$ to get $25$. Thus, $40 - 25 = \boxed{\textbf{(C) }15.}$. ~~Spaced_Out

See also

See also

2020 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
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All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png