2020 AMC 8 Problems/Problem 18
Rectangle 
is inscribed in a semicircle with diameter 
as shown in the figure. Let 
and let 
What is the area of 
![[asy] draw(arc((0,0),17,180,0)); draw((-17,0)--(17,0)); fill((-8,0)--(-8,15)--(8,15)--(8,0)--cycle, 1.5*grey); draw((-8,0)--(-8,15)--(8,15)--(8,0)--cycle); dot("$A$",(8,0), 1.25*S); dot("$B$",(8,15), 1.25*N); dot("$C$",(-8,15), 1.25*N); dot("$D$",(-8,0), 1.25*S); dot("$E$",(17,0), 1.25*S); dot("$F$",(-17,0), 1.25*S); label("$16$",(0,0),N); label("$9$",(12.5,0),N); label("$9$",(-12.5,0),N); [/asy]](http://latex.artofproblemsolving.com/3/c/9/3c9c1a2a36307aa14183c77012405d57721363d4.png)
Solution
First, realize is not a square. It can easily be seen that the diameter of the semicircle is 
, so the radius is 
. Express the area of Rectangle as 
, where 
. Notice that by the Pythagorean theorem 
. Then, the area of Rectangle is equal to 
. ~icematrix
Solution 2
[asy] draw(arc((0,0),17,180,0)); draw((-17,0)--(17,0)); fill((-8,0)--(-8,15)--(8,15)--(8,0)--cycle, 1.5*grey); draw((-8,0)--(-8,15)--(8,15)--(8,0)--cycle); dot("
",(8,0), 1.25*S); dot("
",(8,15), 1.25*N); dot("
",(-8,15), 1.25*N); dot("
",(-8,0), 1.25*S); dot("
",(17,0), 1.25*S); dot("
",(-17,0), 1.25*S); label("
",(0,0),N); label("
",(12.5,0),N); label("",(-12.5,0),N); dot("
", (0,0), 1.25*N);[/asy]
We have 
, as it is a radius, and 
since it is half of 
. This means that 
. So 
~yofro
See also
| 2020 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 17 |
Followed by Problem 19 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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