2014 AMC 8 Problems/Problem 8
Contents
Problem
Eleven members of the Middle School Math Club each paid the same amount for a guest speaker to talk about problem solving at their math club meeting. They paid their guest speaker . What is the missing digit of this -digit number?
Solution 1
Since all the eleven members paid the same amount, that means that the total must be divisible by . We can do some trial-and-error to get , so our answer is . ~SparklyFlowers
Solution 2
We know that a number is divisible by 11 if the odd numbers added together minus the even numbers added together(or vice versa) is a multiple of 11. So, we have = a multiple of ll. The only multiple that works here is 0, as 11x0 = 0. Thus, ~fn106068
See Also
2014 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
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All AJHSME/AMC 8 Problems and Solutions |
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