1976 AHSME Problems/Problem 25
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Problem
For a sequence , define
and, for all integer
.
If
, then
for all
Solution
Note that
Therefore, the answer is
More generally, we have for all
if
~MRENTHUSIASM
See Also
1976 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 24 |
Followed by Problem 26 | |
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