2014 AMC 8 Problems/Problem 13
Problem
If and are integers and is even, which of the following is impossible?
and are even and are odd is even is odd none of these are impossible
Video Solution
https://www.youtube.com/watch?v=boXUIcEcAno
https://youtu.be/_3n4f0v6B7I ~savannahsolver
Solution
Since is even, either both and are even, or they are both odd. Therefore, and are either both even or both odd, since the square of an even number is even and the square of an odd number is odd. As a result, must be even. The answer, then, is .
Solution 2
Instead of using logic to solve this, we can just plug in random numbers. If is even, they are both even or both odd. So just use numbers like 1 and 3. 1+3=4, and 4 is even so the answer is .
~Trex226 .
See Also
2014 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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