1959 AHSME Problems/Problem 11
Problem
The logarithm of 
to the base 
is:
Solution
![\[\log_{2}{0.0625}=\log_{2}{\frac{1}{16}}=\boxed{-4}.\]](http://latex.artofproblemsolving.com/c/a/5/ca5d91d9f245fa7918fe7284f5cdb6f9be7d64a5.png)
See also
| 1959 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
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| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
