2017 AMC 10A Problems/Problem 2

Problem

Pablo buys popsicles for his friends. The store sells single popsicles for $$1$ each, $3$ -popsicle boxes for $$2$ each, and $5$ -popsicle boxes for $$3$ . What is the greatest number of popsicles that Pablo can buy with $$8$ ?

$\textbf{(A)}\ 8\qquad\textbf{(B)}\ 11\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 13\qquad\textbf{(E)}\ 15$

Solution 1

$$3$ boxes give us the most popsicles/dollar, so we want to buy as many of those as possible. After buying $2$ , we have $$2$ left. We cannot buy a third $$3$ box, so we opt for the $$2$ box instead (since it has a higher popsicles/dollar ratio than the $$1$ pack). We're now out of money. We bought $5+5+3=13$ popsicles, so the answer is $\boxed{\textbf{(D) }13}$ .

Video Solution

https://youtu.be/str7kmcRMY8?feature=shared&t=64

(TheBeautyofMath)

Video Solution 2

https://youtu.be/9VGPpemq-qg

~savannahsolver

2017 AMC 10A (Problems • Answer Key • Resources)
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All AMC 10 Problems and Solutions

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2017 AMC 10A Problems/Problem 2

Contents

Problem

Solution 1

Video Solution

Video Solution 2

See Also