2012 AMC 10B Problems/Problem 2

Problem

A circle of radius 5 is inscribed in a rectangle as shown. The ratio of the length of the rectangle to its width is 2:1. What is the area of the rectangle?

$[asy] draw((0,0)--(0,10)--(20,10)--(20,0)--cycle); draw(circle((10,5),5));[/asy]$

$\textbf{(A)}\ 50\qquad\textbf{(B)}\ 100\qquad\textbf{(C)}\ 125\qquad\textbf{(D)}\ 150\qquad\textbf{(E)}\ 200$

Solution

Note that the diameter of the circle is equal to the shorter side of the rectangle. Since the radius is $5$ , the diameter is $2\cdot 5 = 10$ . Since the sides of the rectangle are in a $2:1$ ratio, the longer side has length $2\cdot 10 = 20$ . Therefore the area is $20\cdot 10 = 200$ or $\boxed{\textbf{(E)}\ 200}$

2012 AMC 10B (Problems • Answer Key • Resources)
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2012 AMC 10B Problems/Problem 2

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