1986 AHSME Problems/Problem 1

Problem

$[x-(y-z)] - [(x-y) - z] =$

$\textbf{(A)}\ 2y \qquad \textbf{(B)}\ 2z \qquad \textbf{(C)}\ -2y \qquad \textbf{(D)}\ -2z \qquad \textbf{(E)}\ 0$

The expression becomes $(x-y+z)-(x-y-z) = x-y+z-x+y+z = 2z$ , which is $\boxed{B}$ .

1986 AHSME (Problems • Answer Key • Resources)
Preceded by First Question	Followed by Problem 2
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