2016 AMC 10A Problems/Problem 25
Contents
Problem
How many ordered triples of positive integers satisfy
and
?
Solution 1
We prime factorize and
. The prime factorizations are
,
and
, respectively. Let
,
and
. We know that
and
since
isn't a multiple of 5. Since
we know that
. We also know that since
that
. So now some equations have become useless to us...let's take them out.
are the only two important ones left. We do casework on each now. If
then
or
. Similarly if
then
. Thus our answer is
.
Solution 2
It is well known that if the and
can be written as
, then the highest power of all prime numbers
must divide into either
and/or
. Or else a lower
is the
.
Start from :
so
or
or both. But
because $\text{lcm}(x,z}=600$ (Error compiling LaTeX. Unknown error_msg) and
.
So
.
can be
in both cases of
but NOT
because
and
.
So there are six sets of and we will list all possible values of
based on those.
because
must source all powers of
.
.
because of
restrictions.
By different sourcing of powers of and
,
is "enabled" by
sourcing the power of
.
is uncovered by
sourcing all powers of
. And
is uncovered by
and
both at full power capacity.
Counting the cases,
See Also
2016 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 24 |
Followed by Last Problem | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2016 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 21 |
Followed by Problem 23 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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