2008 AMC 10B Problems/Problem 20
Problem
The faces of a cubical die are marked with the numbers ,
,
,
,
, and
. The faces of another die are marked with the numbers
,
,
,
,
, and
. What is the probability that the sum of the top two numbers will be
,
, or
?
Solution
Solution 1
The easiest way is to write a table of all possible outcomes, do the sums, and count good outcomes.
1 3 4 5 6 8 ------------------ 1 | 2 4 5 6 7 9 2 | 3 5 6 7 8 10 2 | 3 5 6 7 8 10 3 | 4 6 7 8 9 11 3 | 4 6 7 8 9 11 4 | 5 7 8 9 10 12
We see that out of possible outcomes
give the sum of
,
the sum of
, and
the sum of
, hence the resulting probability is
.
Solution 2
Each die is equally likely to roll odd or even, so the probability of an odd sum is .
So we can find the probability of rolling or
instead and just subtract that from
, which seems easier. Without writing out a table, we can see that there are two ways to make
, and two ways to make
, for a probability of
.
.
See also
2008 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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