2008 AMC 10B Problems/Problem 18
Revision as of 03:54, 7 February 2018 by Donotnomath (talk | contribs) (Explained that solution is B.)
Problem
Bricklayer Brenda would take nine hours to build a chimney alone, and bricklayer Brandon would take hours to build it alone. When they work together, they talk a lot, and their combined output decreases by
bricks per hour. Working together, they build the chimney in
hours. How many bricks are in the chimney?
Solution 1
Let be the number of bricks in the chimney. Using
, we get
. Solving for
, we get
.
See also
2008 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.