1956 AHSME Problems/Problem 39
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Problem 39
The hypotenuse and one arm
of a right triangle are consecutive integers. The square of the second arm is:
Solution
The sides of the triangle are
and
We know that the hypotenuse and one leg are consecutive integers, so we can rewrite the side lengths as
and
Squaring the middle length gets so the answer is
The square of the second arm is which is equal to
-coolmath34
See Also
1956 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 38 |
Followed by Problem 40 | |
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