2003 AMC 8 Problems/Problem 12
Problem
When a fair six-sided dice is tossed on a table top, the bottom face cannot be seen. What is the probability that the product of the faces that can be seen is divisible by 
?
Solution
We have six cases: each different case, every one where a different number cannot be seen. The rolls that omit numbers one through five are all something times six: an example would be where the number you cannot see is one, so the product should be 2 x 3 x 4 x 5 x 6, and all of those numbers should be divisible by six. The roll that omits six on the other hand is 1 x 2 x 3 x 4 x 5, which has 2 x 3, also equal to six. We can see that all of them have a factor and therefore are divisible by six, so the solution should be E, 1.
| 2003 AMC 8 (Problems • Answer Key • Resources) | ||
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Followed by Problem 13 | |
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