2010 AMC 8 Problems/Problem 10

Revision as of 12:48, 15 August 2021 by Raina0708 (talk | contribs) (Solution)

Problem

Six pepperoni circles will exactly fit across the diameter of a $12$-inch pizza when placed. If a total of $24$ circles of pepperoni are placed on this pizza without overlap, what fraction of the pizza is covered by pepperoni?

$\textbf{(A)}\ \frac 12 \qquad\textbf{(B)}\ \frac 23 \qquad\textbf{(C)}\ \frac 34 \qquad\textbf{(D)}\ \frac 56 \qquad\textbf{(E)}\ \frac 78$

Solution

The pepperoni circles' diameter is 2, since 12/6= 2 From that we see that the area of the 24 circles of pepperoni is 2/2 24π = 24π The large pizza's area is 6^2π Therefore, the ratio is 24π/36 =2/3

See Also

2010 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
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All AJHSME/AMC 8 Problems and Solutions

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