2023 AMC 12A Problems/Problem 22
Contents
Problem
Let be the unique function defined on the positive integers such that
for all positive integers
. What is
?
Solution 1 (Very Thorough)
First, we note that , since the only divisor of
is itself.
Then, let's look at for
a prime. We see that
Nice.
Now consider , for
.
.
It can be (strongly) inductively shown that . Here's how.
We already showed works. Suppose it holds for
, then
For , we have
, then using
, we simplify to
.
Very nice! Now, we need to show that this function is multiplicative, i.e. for
prime.
It's pretty standard, let's go through it quickly.
Using our formulas from earlier, we have
Great! We're almost done now.
Let's actually plug in into the original formula.
Let's use our formulas! We know
So plugging ALL that in, we have
which, be my guest simplifying, is
~
Solution 2
First, change the problem into an easier form.
So now we get
Also, notice that both
and
are arithmetic functions. Applying Möbius inversion formula, we get
So
So the answer should be
~ZZZIIIVVV
Solution 3
From the problem, we want to find . Using the problem,
. By plugging in factors of
, we get
Notice that
, so
. Similarly, notice that
. Now, substituting this all back into our equation to solve for
, we get
-PhunsukhWangdu
Solution 4
Consider any with prime factorization
.
Thus, the equation given in this problem can be equivalently written as
\noindent \textbf{Special case 1}: .
We have .
\noindent \textbf{Special case 2}: is a prime.
We have
Thus, .
\noindent \textbf{Special case 3}: is the square of a prime,
.
We have
Thus, .
\noindent \textbf{Special case 4}: is the product of two distinct primes,
.
We have
Thus, .
\noindent \textbf{Special case 5}: takes the form
, where
and
are two distinct primes.
We have
Thus, .
The prime factorization of 2023 is .
Therefore,
~Steven Chen (Professor Chen Education Palace, www.professorchenedu.com)
Video Solution by MOP 2024
https://YouTube.com/watch?v=gdhVqdRhMsQ
~r00tsOfUnity
Video Solution by OmegaLearn
Video Solution
~Steven Chen (Professor Chen Education Palace, www.professorchenedu.com)
See also
2023 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 21 |
Followed by Problem 23 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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