1995 AHSME Problems/Problem 4
Revision as of 22:14, 9 January 2008 by Azjps (talk | contribs) (1995 AMC 12 Problems/Problem 4 moved to 1995 AHSME Problems/Problem 4)
Problem
If is
of
,
is
of
, and
is
of
, then
Solution
We are given: ,
,
. We want M in terms of N, so we substitute N into everything:
See also
1995 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |