1995 AHSME Problems/Problem 19
Problem
Equilateral triangle is inscribed in equilateral triangle
such that
. The ratio of the area of
to the area of
is
Solution
Let's take one of the smaller right triangles. Without loss of generality, let the smaller leg be 1. Since the triangle is a 30-60-90 right triangle, then the other leg is \sqrt{3}
\dfrac{1}{3}$.
See also
1995 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
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