2011 AMC 12B Problems/Problem 1
Problem
What is
Solution
Add up the numbers in each fraction to get , which equals . Doing the subtraction yields
$ \boxed{\frac{7}{12}\ \textbf{(C)}}
See also
2011 AMC 12B (Problems • Answer Key • Resources) | |
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Followed by Problem 2 |
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All AMC 12 Problems and Solutions |