2011 AMC 10B Problems/Problem 9
Problem
The area of is one third of the area of . Segment is perpendicular to segment . What is ?
Solution
by AA Similarity. Therefore . Find the areas of the triangles. The area of is one third of the area of .
See Also
2011 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
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All AMC 10 Problems and Solutions |