2017 AMC 10A Problems/Problem 5

Revision as of 16:42, 8 February 2017 by Reaganchoi (talk | contribs) (Solution: 4 is C not D)

Problem

The sum of two nonzero real numbers is 4 times their product. What is the sum of the reciprocals of the two numbers?

$\textbf{(A)}\ 1\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 8\qquad\textbf{(E)}\ 12$

Solution

Let the two real numbers be $x,y$. We are given that

\[x+y=4xy,\]

and dividing both sides by $xy$,

\[\frac{x}{xy}+\frac{y}{xy}=4\]

\[\frac{1}{y}+\frac{1}{x}=\boxed{4 (C)}.\]

See Also

2017 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
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All AMC 10 Problems and Solutions

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