1986 AHSME Problems/Problem 20
Problem
Suppose and are inversely proportional and positive. If increases by , then decreases by
Solution
We see that is multiplied by when it is increased by $p%$ (Error compiling LaTeX. Unknown error_msg). Therefore, is multiplied by , and so it is decreased by times itself. Therefore, it is decreased by $\frac{100p}{100+p}%$ (Error compiling LaTeX. Unknown error_msg), and so the answer is .
See also
1986 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
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