1968 AHSME Problems/Problem 27

Problem

Let $S_n=1-2+3-4+\cdots +(-1)^{n-1}n$ , where $n=1,2,\cdots$ . Then $S_{17}+S_{33}+S_{50}$ equals:

$\text{(A) } 0\quad \text{(B) } 1\quad \text{(C) } 2\quad \text{(D) } -1\quad \text{(E) } -2$

Solution

$\fbox{B}$ It's easy to calculate that if $n$ is even, $Sn$ is negative $n$ over $2$ . If $n$ is odd then $Sn$ is $(n+1)/2$ . Therefore, we know $S(17) + S(33) + S(50) =9+17-25, which is$ \fbox{B}$.

1968 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 26	Followed by Problem 28
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1968 AHSME Problems/Problem 27

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