Create the page "Mc ade" on this wiki! See also the search results found.

• 2010 AIME II Problems
  ...ion of the circumcircles of <math>\triangle AMN</math> and <math>\triangle ADE</math>. Ray <math>AP</math> meets <math>BC</math> at <math>Q</math>. The ra
  8 KB (1,246 words) - 21:58, 10 August 2020
• 2010 AIME II Problems/Problem 15
  ...ion of the circumcircles of <math>\triangle AMN</math> and <math>\triangle ADE</math>. Ray <math>AP</math> meets <math>BC</math> at <math>Q</math>. The ra ...ince <math>Q</math> lies on the radical axis of <math>(AMN)</math>, <math>(ADE)</math> thus <cmath>\frac{BQ}{CQ}=-\frac{f(B)}{f(C)}=-\frac{BN\cdot BA-BE\c
  9 KB (1,523 words) - 15:24, 21 November 2023
• 2016 IMO Problems/Problem 1
  ...th>\angle FBA = \angle FAB = \angle FAD = \angle FCD = \angle DAE = \angle ADE = \alpha</math>. And WLOG, <math>MF = 1</math>. Hence, <math>CF = 2</math>, ...th> are concyclic. We know that <math>DE || MC</math> and <math>DE = 1 = MC</math>, so we conclude <math>MCDE</math> is parallelogram. So <math>\angle
  3 KB (559 words) - 10:06, 27 May 2024
• G285 2021 Summer Problem Set
  ...</math>. If there exists a point <math>P</math> outside of <math>\triangle ADE</math> such that <math>AP=PD=28</math>, and there exists a point <math>O</m [[G285 2021 MC-IME I Problem 1|Solution]]
  9 KB (1,577 words) - 23:28, 28 June 2021
• Miquel's point
  ...ete quadrilateral. In the diagram these are <math>\triangle ABC, \triangle ADE, \triangle CEF, \triangle BDF.</math> <math>AD||GF \implies \angle ADE + \angle DFG = 180^\circ \implies \angle ADE + \angle AME = 180^\circ \implies</math>
  6 KB (976 words) - 23:10, 28 October 2023