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  • \text{(O) }\frac{1}{2^{14}}\qquad
    2 KB (247 words) - 03:34, 14 June 2018
  • \text{(O) } 14 \quad
    929 bytes (137 words) - 22:05, 10 January 2019
  • \text{(O) } 14\qquad
    2 KB (270 words) - 14:35, 29 July 2018
  • Let <math>O</math> denote the circumcentre of an acute-angled triangle <math>ABC</math>
    2 KB (381 words) - 13:45, 8 October 2014
  • ...</math> are fixed points on a given circle not collinear with center <math>O</math> of the circle, and if <math>XY</math> is a variable diameter, find t
    445 bytes (76 words) - 17:51, 8 October 2014
  • \text{(O) } 3-2i\quad</math>
    1 KB (202 words) - 16:48, 24 November 2018
  • \text{(O) }14 \quad
    2 KB (340 words) - 19:49, 30 June 2018
  • ...inute hand passes the hour hand at the usual dial position(<math>12</math> o'clock, etc.)
    18 KB (2,703 words) - 20:50, 11 September 2023
  • pair O = circumcenter(A,B,C); dot(O);
    8 KB (1,480 words) - 14:52, 5 August 2022
  • pair O = circumcenter(H,S,T); path circle2 = Circle(O, length(O-H));
    6 KB (1,071 words) - 03:58, 8 September 2018
  • ...ts are drawn connecting these points to each other and to the origin <math>O</math>.
    19 KB (2,907 words) - 14:16, 20 February 2020
  • ...d <math>\triangle ABC</math> is inscribed in a circle with center at <math>O</math>; <math>\stackrel \frown {AB} = 120</math> and <math>\stackrel \frown
    20 KB (3,122 words) - 14:17, 20 February 2020
  • Circle <math>O</math> has diameters <math>AB</math> and <math>CD</math> perpendicular to e pair O = origin;
    26 KB (3,952 words) - 20:24, 10 June 2024
  • The points <math>A,B,C</math> are on a circle <math>O</math>. The tangent line at <math>A</math> and the secant <math>BC</math> i Triangle <math>PAB</math> is formed by three tangents to circle <math>O</math> and <math>\angle APB = 40^{\circ}</math>; then <math>\angle AOB</mat
    20 KB (3,039 words) - 22:44, 12 February 2021
  • pair O=(-sqrt(3)/2,-1/2),E=(sqrt(3),0),NW=(-sqrt(3)/2,3/2),NE=(sqrt(3)/2,3/2),SE=( ...+2E+NE)--(O+2E+NE+SE)--(O+2E+2NE+SE)--(O+2E+2NE+SE+NW)--(O+3E+2NE+SE+NW)--(O+3E+3NE+SE+NW),black+linewidth(2));
    6 KB (982 words) - 15:11, 22 October 2018
  • pair O=(-sqrt(3)/2,-1/2),E=(sqrt(3),0),NW=(-sqrt(3)/2,3/2),NE=(sqrt(3)/2,3/2),SE=( ...+2E+NE)--(O+2E+NE+SE)--(O+2E+2NE+SE)--(O+2E+2NE+SE+NW)--(O+3E+2NE+SE+NW)--(O+3E+3NE+SE+NW),black+linewidth(2));
    3 KB (628 words) - 19:22, 20 May 2021
  • Let <math>OM</math> be the inscribed circle's radius, with <math>O</math> being its center and <math>M</math> being the midpoint of <math>AB</
    3 KB (412 words) - 18:49, 29 January 2018
  • ...CD</math>, and <math>BC</math> is tangent to the circle with center <math>O</math> and diameter <math>AD</math>. pair O=origin, A=(-1/sqrt(2),1/sqrt(2)), B=(-1/sqrt(2),-1), C=(1/sqrt(2),-1), D=(1
    1 KB (261 words) - 22:22, 13 August 2023
  • respectively. Let <math>O</math> be the center of the pentagon. If <math>OP = 1</math>, then <math>AO pair O=origin, A=2*dir(90), B=2*dir(18), C=2*dir(306), D=2*dir(234), E=2*dir(162),
    4 KB (702 words) - 17:13, 17 April 2020
  • The circumference of the circle with center <math>O</math> is divided into 12 equal arcs, marked the letters <math>A</math> thr pair O=origin;
    13 KB (1,957 words) - 12:08, 13 January 2024

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