2019 AMC 10A Problems/Problem 2
Revision as of 23:41, 30 June 2020 by Scrabbler94 (talk | contribs) (Solution 2 is wrong since divisibility by 100 doesn't imply the hundreds digit of their difference is 0.)
Contents
Problem
What is the hundreds digit of 
Solution
The last three digits of 
for all 
are 
, because there are at least three 
s and three 
s in its prime factorization. Because 
, the answer is 
.
Video Solution
~savannahsolver
See Also
| 2019 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
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| All AMC 10 Problems and Solutions | ||
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