1959 AHSME Problems/Problem 16
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Problem 16
The expression when simplified is:
Solution
Factoring each of the binomials in the expression will yield the result of We can eliminate like terms to get , which, according to identity property, is equivalent to the answer (D) 1.
See also
1959 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 17 | |
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