2020 AMC 8 Problems/Problem 3

Problem 3

Carrie has a rectangular garden that measures $6$ feet by $8$ feet. She plants the entire garden with strawberry plants. Carrie is able to plant $4$ strawberry plants per square foot, and she harvests an average of $10$ strawberries per plant. How many strawberries can she expect to harvest?

$\textbf{(A) }560 \qquad \textbf{(B) }960 \qquad \textbf{(C) }1120 \qquad \textbf{(D) }1920 \qquad \textbf{(E) }3840$

Solution

The answer is the product of the area of the field, the amount of strawberries per plant, and the amount of plants in one square feet. The answer is $6 \times 8 \times 10 \times 4 = 1920$ or $\boxed{\textbf{D }1920}$ .

Solution 2

The area of the garden is $6$ ft $\times 8$ ft $= 48$ square feet. Since Carrie plants $4$ strawberry plants per square foot, it follows that she plants a total of $48 \times 4=192$ strawberry plants. Since each strawberry plant produces on average 10 strawberries, it follows that she can expect to harvest $192 \times 10=1920$ strawberries $\implies\boxed{\textbf{(D) }1920}$ .
~jmansuri

2020 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

Page

Toolbox

Search

2020 AMC 8 Problems/Problem 3

Contents

Problem 3

Solution

Solution 2

See also