1982 AHSME Problems/Problem 29
Problem
Let , and be three positive real numbers whose sum is . If no one of these numbers is more than twice any other, then the minimum possible value of the product is
Solution
The answer is A, 1/32, as obtained by (1/4) * (1/4) * (1/2).
See Also
1982 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 28 |
Followed by Problem 30 | |
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